Solve using elimination. –2x + 3y = –16 x + 3y = –10 (_____, _____)

Write Equations: Write down the system of equations to be solved using elimination. –2x + 3y = –16 x + 3y = –10Multiply Second Equation: Multiply the second equation by 2 so that the x terms can be eliminated when the two equations are added together. 2(x + 3y) = 2(–10) 2x + 6y = –20Add Equations: Add the modified second equation to the first equation to eliminate the x terms. (–2x + 3y) + (2x + 6y) = (–16) + (–20) 0x + 9y = –36Solve for y: Solve for y by dividing both sides of the equation by 9. 9y = –36 y = –36 / 9 y = –4Substitute y into Equation: Substitute y = –4 into the original second equation to solve for x. x + 3(–4) = –10 x - 12 = –10Solve for x: Add 12 to both sides of the equation to solve for x. x - 12 + 12 = –10 + 12 x = 2

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Solve using elimination. $\newline$ $-2x + 3y = -16$ $\newline$ $x + 3y = -10$ $\newline$ (_, _)

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Grade 8

Solve a system of equations using elimination

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Q. Solve using elimination.

\newline

-2x + 3y = -16

\newline

x + 3y = -10

\newline

(_____, _____)

Write Equations: Write down the system of equations to be solved using elimination. $\newline$ $-2x + 3y = -16$ $\newline$ $x + 3y = -10$
Multiply Second Equation: Multiply the second equation by $2$ so that the $x$ terms can be eliminated when the two equations are added together. $\newline$ $2(x + 3y) = 2(–10)$ $\newline$ $2x + 6y = –20$
Add Equations: Add the modified second equation to the first equation to eliminate the $x$ terms. $\newline$ $(-2x + 3y) + (2x + 6y) = (-16) + (-20)$ $\newline$ $0x + 9y = -36$
Solve for y: Solve for y by dividing both sides of the equation by $9$ . $\newline$ $9y = -36$ $\newline$ $y = -36 / 9$ $\newline$ $y = -4$
Substitute $y$ into Equation: Substitute $y = -4$ into the original second equation to solve for $x$ . $x + 3(-4) = -10$ $x - 12 = -10$
Solve for x: Add $12$ to both sides of the equation to solve for x. $\newline$ $x - 12 + 12 = -10 + 12$ $\newline$ $x = 2$