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Solve using elimination.\newline2x2y=6-2x - 2y = 6\newlinex+2y=2x + 2y = 2\newline(_____, _____)

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Q. Solve using elimination.\newline2x2y=6-2x - 2y = 6\newlinex+2y=2x + 2y = 2\newline(_____, _____)
  1. Write Equations: Write down the system of equations to be solved using elimination.\newline2x2y=6-2x - 2y = 6\newlinex+2y=2x + 2y = 2
  2. Add Equations: Add the two equations together to eliminate the yy variable.\newline(2x2y)+(x+2y)=6+2(-2x - 2y) + (x + 2y) = 6 + 2
  3. Find xx: Perform the addition to find the value of xx.
    2x+x=6+2–2x + x = 6 + 2
    x=8–x = 8
  4. Solve for x: Solve for x by dividing both sides by 1–1.x=8(1)x = \frac{8}{(–1)}x=8x = –8
  5. Substitute xx for yy: Substitute the value of xx back into one of the original equations to solve for yy. We'll use the second equation: x+2y=2x + 2y = 2.\newline(8)+2y=2(–8) + 2y = 2
  6. Isolate y term: Add 88 to both sides to isolate the term with yy.\newline2y=2+82y = 2 + 8\newline2y=102y = 10
  7. Solve for y: Divide both sides by 22 to solve for y.\newliney=102y = \frac{10}{2}\newliney=5y = 5

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