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Solve using elimination.\newline2x2y=22x - 2y = -2\newline2x8y=202x - 8y = -20\newline(_____, _____)

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Q. Solve using elimination.\newline2x2y=22x - 2y = -2\newline2x8y=202x - 8y = -20\newline(_____, _____)
  1. Write Equations: First, let's write down the system of equations we need to solve:\newline2x2y=22x − 2y = −2\newline2x8y=202x − 8y = −20\newlineWe want to eliminate one of the variables by subtracting one equation from the other. Since the coefficients of xx are the same, we can subtract the second equation from the first one to eliminate xx.
  2. Subtract Equations: Perform the subtraction of the two equations:\newline(2x2y)(2x8y)=(2)(20)(2x − 2y) − (2x − 8y) = (−2) − (−20)\newlineThis simplifies to:\newline2x2x2y+8y=2+202x − 2x − 2y + 8y = −2 + 20
  3. Simplify Result: Simplify the resulting equation:\newline0x+6y=180x + 6y = 18\newlineSince 0x0x is 00, we can remove it from the equation:\newline6y=186y = 18
  4. Solve for y: Now, we solve for yy by dividing both sides of the equation by 66:6y6=186\frac{6y}{6} = \frac{18}{6}y=3y = 3
  5. Substitute and Solve: With the value of yy found, we can substitute it back into one of the original equations to find xx. Let's use the first equation:\newline2x2(3)=22x − 2(3) = −2\newline2x6=22x − 6 = −2
  6. Addition to Solve xx: Add 66 to both sides of the equation to solve for xx:2x6+6=2+62x − 6 + 6 = −2 + 62x=42x = 4
  7. Final Solution: Finally, divide both sides by 22 to find the value of xx:2x2=42\frac{2x}{2} = \frac{4}{2}x=2x = 2

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