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Solve using elimination.\newline2x10y=6-2x - 10y = 6\newline2x8y=8-2x - 8y = 8\newline(_____, _____)

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Q. Solve using elimination.\newline2x10y=6-2x - 10y = 6\newline2x8y=8-2x - 8y = 8\newline(_____, _____)
  1. Write Equations: Write down the system of equations.\newline2x10y=6-2x - 10y = 6\newline2x8y=8-2x - 8y = 8
  2. Modify Second Equation: To use elimination, we want to eliminate one of the variables. We can do this by adding the two equations together. However, since both equations have the term 2x–2x, we need to make one of them positive so that when we add the equations, the xx terms cancel out. We can multiply the second equation by 1-1 to achieve this.\newlineMultiplying the second equation by 1-1 gives us:\newline2x+8y=82x + 8y = -8
  3. Add Equations: Now add the modified second equation to the first equation to eliminate the xx variable.\newline(2x10y)+(2x+8y)=6+(8)(-2x - 10y) + (2x + 8y) = 6 + (-8)
  4. Simplify Equation: Perform the addition to eliminate the xx variable.2x+2x10y+8y=68\,-2x + 2x - 10y + 8y = 6 - 80x2y=2\,0x - 2y = -2
  5. Substitute yy: Simplify the resulting equation to solve for yy.\newline2y=2−2y = -2\newliney=2/2y = -2 / -2\newliney=1y = 1
  6. Solve for x: Now that we have the value of yy, we can substitute it back into one of the original equations to solve for xx. Let's use the first equation:\newline2x10y=6–2x − 10y = 6\newlineSubstitute y=1y = 1:\newline2x10(1)=6–2x − 10(1) = 6
  7. Solve for x: Now that we have the value of yy, we can substitute it back into one of the original equations to solve for xx. Let's use the first equation:\newline2x10y=6-2x - 10y = 6\newlineSubstitute y=1y = 1:\newline2x10(1)=6-2x - 10(1) = 6 Solve for xx.\newline2x10=6-2x - 10 = 6\newlineAdd 1010 to both sides:\newline2x=6+10-2x = 6 + 10\newline2x=16-2x = 16\newlineDivide both sides by xx00:\newlinexx11\newlinexx22

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