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Solve using augmented matrices.\newliney=3y = 3\newline–6x−4y=6–6x − 4y = 6\newline(_____, _____)

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Full solution

Q. Solve using augmented matrices.\newliney=3y = 3\newline–6x−4y=6–6x − 4y = 6\newline(_____, _____)
  1. Prompt: question_prompt: What is the solution to the system of equations using augmented matrices?
  2. Write Matrix: Write the system of equations as an augmented matrix.
  3. Leading Coefficient: Perform row operations to get the leading coefficient of the first row to be 11. Oh wait, it's already 00 for xx and 11 for yy, so we can skip this step.
  4. Find xx: Now, let's use the second equation to find the value of xx. We can directly substitute y=3y = 3 into the second equation.
  5. Simplify Equation: Simplify the equation by multiplying 44 by 33 and moving it to the other side.
  6. Find xx Value: Divide both sides by −6-6 to find the value of xx.
  7. Final Values: Now we have the values for xx and yy.

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