Solve using augmented matrices. y = –10 –4x − 2y = –16 (_____, _____)

Write Equations in Standard Form: Step 1: Write the system of equations in standard form. y = -10 -4x - 2y = -16Substitute y into Second Equation: Step 2: Substitute y = -10 into the second equation. -4x - 2(-10) = -16 -4x + 20 = -16Solve for x: Step 3: Solve for x. -4x + 20 - 20 = -16 - 20 -4x = -36 x = -36 / -4 x = 9Check Solution: Step 4: Check the solution in the original equations. Substitute x = 9 and y = -10 into the equations. First equation: y = -10 (True) Second equation: -4(9) - 2(-10) = -16 -36 + 20 = -16 (True)

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Solve using augmented matrices. $\newline$ $y = -10$ $\newline$ $-4x - 2y = -16$ $\newline$ (_, _)

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Grade 8

Solve a system of equations using any method

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Q. Solve using augmented matrices.

\newline

y = -10

\newline

-4x - 2y = -16

\newline

(_____, _____)

Write Equations in Standard Form: Step $1$ : Write the system of equations in standard form. $\newline$ $y = -10$ $\newline$ $-4x - 2y = -16$
Substitute $y$ into Second Equation: Step $2$ : Substitute $y = -10$ into the second equation. $\newline$ $-4x - 2(-10) = -16$ $\newline$ $-4x + 20 = -16$
Solve for x: Step $3$ : Solve for x. $\newline$ $-4x + 20 - 20 = -16 - 20$ $\newline$ $-4x = -36$ $\newline$ $x = -36 / -4$ $\newline$ $x = 9$
Check Solution: Step $4$ : Check the solution in the original equations. $\newline$ Substitute $x = 9$ and $y = -10$ into the equations. $\newline$ First equation: $y = -10$ (True) $\newline$ Second equation: $-4(9) - 2(-10) = -16$ $\newline$ $-36 + 20 = -16$ (True)