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Solve using augmented matrices.\newline5x7y=1-5x - 7y = 1\newliney=7y = 7\newline(_____, _____)

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Q. Solve using augmented matrices.\newline5x7y=1-5x - 7y = 1\newliney=7y = 7\newline(_____, _____)
  1. Write Augmented Matrix: First, let's write the system of equations as an augmented matrix.\newlineThe system is:\newline5x7y=1-5x - 7y = 1\newliney=7y = 7\newlineWe can represent this as:\newline[5amp;7amp;amp;1 0amp;1amp;amp;7]\begin{bmatrix} -5 & -7 & \vert & 1 \ 0 & 1 & \vert & 7 \end{bmatrix}
  2. Eliminate yy Term: Now, we need to use the second equation y=7y = 7 to eliminate the yy term from the first equation.\newlineWe can multiply the second row by 77 and add it to the first row.\newlineBut since the second row already represents y=7y = 7, we don't need to do any operations.
  3. Substitute and Solve: Next, we substitute y=7y = 7 into the first equation.5x7(7)=1-5x - 7(7) = 15x49=1-5x - 49 = 1
  4. Find xx: Now, we solve for xx.5x=1+49\,-5x = 1 + 495x=50\,-5x = 50x=50/(5)\,x = 50 / (\,-5)x=10\,x = \,-10
  5. Final Solution: We have found the value of xx, and we already know the value of yy from the second equation.\newlineSo, the solution to the system of equations is:\newlinex=10x = -10, y=7y = 7

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