Solve using augmented matrices. –3x + 6y = –18 x = –10 (_____, _____)

Write Augmented Matrix: First, let's write the system of equations as an augmented matrix.Eliminate x-term: The system is: –3x + 6y = –18 x = –10 We can represent this as: [ -3 6 | -18 ] [ 1 0 | -10 ]Solve for y: Now, let's use the second equation to eliminate the x-term in the first equation by adding 3 times the second row to the first row.Divide by 6: After the row operation, the augmented matrix looks like this: [ 0 6 | -48 ] [ 1 0 | -10 ]Find x and y: Next, we can solve for y by dividing the first row by 6.Dividing the first row by 6 gives us: [ 0 1 | -8 ] [ 1 0 | -10 ]Now we have the values for x and y directly from the matrix: x = -10 y = -8

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Solve using augmented matrices. $\newline$ $-3x + 6y = -18$ $\newline$ $x = -10$ $\newline$ $(\_, \_)$

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Precalculus

Solve a system of equations using elimination

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Q. Solve using augmented matrices.

\newline

-3x + 6y = -18

\newline

x = -10

\newline

(\_, \_)

Write Augmented Matrix: First, let's write the system of equations as an augmented matrix.
Eliminate x-term: The system is: $\newline$ $-3x + 6y = -18$ $\newline$ $x = -10$ $\newline$ We can represent this as: $\newline$ $\begin{bmatrix} -3 & 6 & | & -18 \ 1 & 0 & | & -10 \end{bmatrix}$
Solve for $y$ : Now, let's use the second equation to eliminate the $x$ -term in the first equation by adding $3$ times the second row to the first row.
Divide by $6$ : After the row operation, the augmented matrix looks like this: $\newline$ \begin{array}{cc|c} 0 & 6 & -48 \ 1 & 0 & -10 \end{array}
Find $x$ and $y$ : Next, we can solve for $y$ by dividing the first row by $6$ .
Find $x$ and $y$ : Next, we can solve for $y$ by dividing the first row by $6$ .Dividing the first row by $6$ gives us: $\newline$ \begin{array}{cc|c} 0 & 1 & -8 \ 1 & 0 & -10 \end{array}
Find $x$ and $y$ : Next, we can solve for $y$ by dividing the first row by $6$ .Dividing the first row by $6$ gives us: $\newline$ $\begin{matrix} 0 & 1 & | & -8 \ 1 & 0 & | & -10 \end{matrix}$ Now we have the values for $x$ and $y$ directly from the matrix: $\newline$ $x = -10$ $\newline$ $y = -8$