Solve the system of equations.y=x2−11x+27y=−22x+3Write the coordinates in exact form. Simplify all fractions and radicals.(______,______)(______,______)
Q. Solve the system of equations.y=x2−11x+27y=−22x+3Write the coordinates in exact form. Simplify all fractions and radicals.(______,______)(______,______)
Set Equations Equal: We have the system of equations:y=x2−11x+27y=−22x+3To find the solution, we will set the two equations equal to each other because they both equal y.x2−11x+27=−22x+3
Rearrange and Standardize: Now we will rearrange the equation to bring all terms to one side and set it equal to zero, which will give us a standard form of a quadratic equation.x2−11x+27+22x−3=0Combining like terms, we get:x2+11x+24=0
Factor Quadratic Equation: Next, we need to factor the quadratic equation. We are looking for two numbers that multiply to 24 and add up to 11. These numbers are 8 and 3. So we can write the factored form as: (x+8)(x+3)=0
Solve for x: Now we will solve for x by setting each factor equal to zero.First, for (x+8)=0, we get x=−8.Second, for (x+3)=0, we get x=−3.
Find y-values: With the x-values found, we now need to find the corresponding y-values. We can substitute x back into either of the original equations. We'll use the second equation y=−22x+3 for simplicity.For x=−8, we substitute into the equation to get y=−22(−8)+3=176+3=179.For x=−3, we substitute into the equation to get y=−22(−3)+3=66+3=69.
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