Solve the system of equations.y=−42x+50y=x2−42x−50Write the coordinates in exact form. Simplify all fractions and radicals.(______,______)(______,______)
Q. Solve the system of equations.y=−42x+50y=x2−42x−50Write the coordinates in exact form. Simplify all fractions and radicals.(______,______)(______,______)
Set Equations Equal: We have the system of equations:y=−42x+50y=x2−42x−50To find the solution, we will set the two equations equal to each other since they both equal y.−42x+50=x2−42x−50
Simplify and Rearrange: Now we simplify the equation by moving all terms to one side to set the equation to zero.−42x+50−(−42x)−50=x2−42x−50−(−42x)−500=x2−50
Solve Quadratic Equation: We now have a simple quadratic equation:x2−50=0To solve for x, we can add 50 to both sides of the equation.x2=50
Find x-values: Next, we take the square root of both sides to solve for x.x=50 or x=−50Since 50 can be simplified to 52, we have:x=52 or x=−52
Substitute x-values: We now have two possible values for x. We need to find the corresponding y-values for each x-value by substituting them back into one of the original equations. We can use the simpler equation y=−42x+50. First, let's substitute x=52: y=−42×(52)+50 y=−2102+50
Final Coordinates: Now let's substitute x=−52:y=−42(−52)+50y=2102+50
Final Coordinates: Now let's substitute x=−52:y=−42(−52)+50y=2102+50We now have the two sets of coordinates in exact form:First Coordinate: (52,−2102+50)Second Coordinate: (−52,2102+50)
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