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Solve the system of equations.\newliney=42x+50y = -42x + 50\newliney=x242x50y = x^2 - 42x - 50\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)

Full solution

Q. Solve the system of equations.\newliney=42x+50y = -42x + 50\newliney=x242x50y = x^2 - 42x - 50\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
  1. Set Equations Equal: We have the system of equations:\newliney=42x+50y = -42x + 50\newliney=x242x50y = x^2 - 42x - 50\newlineTo find the solution, we will set the two equations equal to each other since they both equal yy.\newline42x+50=x242x50-42x + 50 = x^2 - 42x - 50
  2. Simplify and Rearrange: Now we simplify the equation by moving all terms to one side to set the equation to zero.\newline42x+50(42x)50=x242x50(42x)50-42x + 50 - (-42x) - 50 = x^2 - 42x - 50 - (-42x) - 50\newline0=x2500 = x^2 - 50
  3. Solve Quadratic Equation: We now have a simple quadratic equation:\newlinex250=0x^2 - 50 = 0\newlineTo solve for x, we can add 5050 to both sides of the equation.\newlinex2=50x^2 = 50
  4. Find x-values: Next, we take the square root of both sides to solve for xx.x=50x = \sqrt{50} or x=50x = -\sqrt{50}Since 50\sqrt{50} can be simplified to 525\sqrt{2}, we have:x=52x = 5\sqrt{2} or x=52x = -5\sqrt{2}
  5. Substitute x-values: We now have two possible values for xx. We need to find the corresponding yy-values for each xx-value by substituting them back into one of the original equations. We can use the simpler equation y=42x+50y = -42x + 50.
    First, let's substitute x=52x = 5\sqrt{2}:
    y=42×(52)+50y = -42\times(5\sqrt{2}) + 50
    y=2102+50y = -210\sqrt{2} + 50
  6. Final Coordinates: Now let's substitute x=52x = -5\sqrt{2}:y=42(52)+50y = -42(-5\sqrt{2}) + 50y=2102+50y = 210\sqrt{2} + 50
  7. Final Coordinates: Now let's substitute x=52x = -5\sqrt{2}:y=42(52)+50y = -42(-5\sqrt{2}) + 50y=2102+50y = 210\sqrt{2} + 50We now have the two sets of coordinates in exact form:First Coordinate: (52,2102+50)(5\sqrt{2}, -210\sqrt{2} + 50)Second Coordinate: (52,2102+50)(-5\sqrt{2}, 210\sqrt{2} + 50)

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