Solve the system of equations. y = 39x + 4 y = 48x^2 + 39x - 44 Write the coordinates in exact form. Simplify all fractions and radicals. (______,______) (______,______)

Set Equations Equal: Set the two equations equal to each other since they both equal y. 39x + 4 = 48x^2 + 39x - 44Subtract to Get Quadratic: Subtract 39x from both sides to get the quadratic equation. 4 = 48x^2 - 44Add to Isolate Term: Add 44 to both sides to isolate the quadratic term. 48x^2 = 48Divide to Solve: Divide both sides by 48 to solve for x^2. x^2 = 1Take Square Root: Take the square root of both sides to find the values of x. x = 1 or x = -1Find x = 1: Plug x = 1 into the first equation to find the corresponding y-value. y = 39(1) + 4 y = 43Find x = -1: Plug x = -1 into the first equation to find the corresponding y-value. y = 39(-1) + 4 y = -35Write Coordinates: Write the coordinates in exact form. First Coordinate: (1, 43) Second Coordinate: (-1, -35)

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Solve the system of equations. $\newline$ $y = 39x + 4$ $\newline$ $y = 48x^2 + 39x - 44$ $\newline$ Write the coordinates in exact form. Simplify all fractions and radicals. $\newline$ (,) $\newline$ (,)

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Algebra 2

Solve a system of linear and quadratic equations: parabolas

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Q. Solve the system of equations.

\newline

y = 39x + 4

\newline

y = 48x^2 + 39x - 44

\newline

Write the coordinates in exact form. Simplify all fractions and radicals.

\newline

(______,______)

\newline

(______,______)

Set Equations Equal: Set the two equations equal to each other since they both equal $y$ . $39x + 4 = 48x^2 + 39x - 44$
Subtract to Get Quadratic: Subtract $39x$ from both sides to get the quadratic equation. $\newline$ $4 = 48x^2 - 44$
Add to Isolate Term: Add $44$ to both sides to isolate the quadratic term. $\newline$ $48x^2 = 48$
Divide to Solve: Divide both sides by $48$ to solve for $x^2$ . $\newline$ $x^2 = 1$
Take Square Root: Take the square root of both sides to find the values of $x$ . $x = 1$ or $x = -1$
Find $x = 1$ : Plug $x = 1$ into the first equation to find the corresponding y-value. $\newline$ $y = 39(1) + 4$ $\newline$ $y = 43$
Find $x = -1$ : Plug $x = -1$ into the first equation to find the corresponding y-value. $\newline$ $y = 39(-1) + 4$ $\newline$ $y = -35$
Write Coordinates: Write the coordinates in exact form. $\newline$ First Coordinate: $(1, 43)$ $\newline$ Second Coordinate: $(-1, -35)$