Solve the system of equations.y=21x+41y=x2+21x−23Write the coordinates in exact form. Simplify all fractions and radicals.(______,______)(______,______)
Q. Solve the system of equations.y=21x+41y=x2+21x−23Write the coordinates in exact form. Simplify all fractions and radicals.(______,______)(______,______)
Substitute y into second equation: Substitute y from the first equation into the second equation: y=x2+21x−23 becomes 21x+41=x2+21x−23.
Subtract 21x: Subtract 21x from both sides to get 41=x2−23.
Add 23: Add 23 to both sides to find x2=64.
Take square root: Take the square root of both sides to find x=±8.
Substitute x=8 into y: Substitute x=8 into y=21x+41 to find y. This gives us y=21(8)+41.
Calculate y for x=8: Calculate y for x=8: y=168+41, which is y=209.
Substitute x=−8 into y: Now substitute x=−8 into y=21x+41 to find y. This gives us y=21(−8)+41.
Calculate y for x=−8: Calculate y for x=−8: y=−168+41, which is y=−127.
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