Q. Solve the system of equations by substitution.2x−3y−2z=−152x−2y+3z=0z=2
Start with z=2: Solve the system of equations by substitution, starting with the third equation given, z=2.
Substitute z into equations: Substitute z=2 into the first two equations.2x−3y−2(2)=−152x−2y+3(2)=0
Simplify after substitution: Simplify the equations after substitution.2x−3y−4=−152x−2y+6=0
Isolate x and y terms: Add 4 to both sides of the first equation and subtract 6 from both sides of the second equation to isolate the terms with x and y.2x−3y=−112x−2y=−6
Solve for x: Now, let's solve one of the equations for x. We can take the second equation, 2x−2y=−6, and solve for x.2x=2y−6x=y−3
Substitute x into equation: Substitute x=y−3 into the first simplified equation.2(y−3)−3y=−11
Combine like terms: Distribute and combine like terms. 2y−6−3y=−11
Simplify by combining y terms: Simplify the equation by combining y terms. −y−6=−11
Solve for y: Add 6 to both sides of the equation to solve for y.−y=−5
Substitute y into x: Multiply both sides by −1 to get the value of y.y=5
Calculate x: Substitute y=5 into x=y−3 to find the value of x.x=5−3
Calculate x: Substitute y=5 into x=y−3 to find the value of x.x=5−3Calculate the value of x.x=2
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