Q. Solve the system of equations by elimination.3x+2y+2z=−20−x+2y−2z=−4x+y+3z=2
Add Equations: Step 1: Add the first and second equations to eliminate x.3x+2y+2z=−20+(−x+2y−2z)=−42x+4y=−24
Multiply Third Equation: Step 2: Multiply the third equation by 3 to prepare to eliminate x with the second equation.3(x+y+3z)=3(2)3x+3y+9z=6
Add Modified Equations: Step 3: Add the modified third equation and the second equation to eliminate x.3x+3y+9z=6+(−x+2y−2z)=−4-------------------2x+5y+7z=2
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