Q. Solve the system of equations by elimination.−2x−3y+z=18−x+2y−2z=−17−2x+y−2z=−13
Add Equations to Eliminate y: First, let's add the first and third equations to eliminate y.−2x−3y+z+(−2x+y−2z)=18+(−13)−4x−2y−z=5
Multiply and Add Equations: Now, let's multiply the second equation by 2 so we can add it to the first equation and eliminate y. −2(−x+2y−2z)=−2(−17) 2x−4y+4z=34
Add Modified Equations: Add the modified second equation to the first equation.(−2x−3y+z)+(2x−4y+4z)=18+34−7y+5z=52
Solve for z: Now we have two new equations:−4x−2y−z=5−7y+5z=52Let's solve for z by multiplying the first new equation by 5 and the second new equation by 1 so we can add them and eliminate y.5(−4x−2y−z)=5(5)−7y+5z=52
Add Equations to Eliminate y: After multiplying we get:−20x−10y−5z=25−7y+5z=52Now, let's add these two equations.(−20x−10y−5z)+(−7y+5z)=25+52−20x−17y=77
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