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Solve the system of equations. −9x+4y=6-9x + 4y = 6 and 9x+5y=−339x + 5y = -33

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Q. Solve the system of equations. −9x+4y=6-9x + 4y = 6 and 9x+5y=−339x + 5y = -33
  1. Combine equations: Add the two equations together to eliminate the xx variable.\newline−9x+4y=6-9x + 4y = 6\newline+9x+5y=−33+ 9x + 5y = -33\newline-----------------\newline9y=−279y = -27
  2. Solve for y: Divide both sides of the equation 9y=−279y = -27 by 99 to solve for y.\newliney=−27/9y = -27 / 9\newliney=−3y = -3
  3. Substitute y into equation: Substitute y=−3y = -3 into one of the original equations to solve for xx. We'll use the first equation −9x+4y=6-9x + 4y = 6.
    −9x+4(−3)=6-9x + 4(-3) = 6
    −9x−12=6-9x - 12 = 6
  4. Isolate x term: Add 1212 to both sides of the equation to isolate the term with xx.\newline−9x−12+12=6+12-9x - 12 + 12 = 6 + 12\newline−9x=18-9x = 18
  5. Solve for x: Divide both sides of the equation −9x=18-9x = 18 by −9-9 to solve for x.\newlinex=18−9x = \frac{18}{-9}\newlinex=−2x = -2

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