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Solve the system by substitution.

{:[y=-x+36],[y=3x]:}

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Solve the system by substitution.\newliney=x+36y=3x \begin{array}{l} y=-x+36 \\ y=3 x \end{array} \newline(,) (\square, \square)

Full solution

Q. Solve the system by substitution.\newliney=x+36y=3x \begin{array}{l} y=-x+36 \\ y=3 x \end{array} \newline(,) (\square, \square)
  1. Identify Equation to Substitute: First, we need to identify which equation to substitute into the other. Since the first equation gives us yy in terms of xx, we can substitute this expression for yy into the second equation.
  2. Substitute yy into Second Equation: Substitute y=x+36y = -x + 36 into the second equation y=3xy = 3x.\newlineSo, x+36=3x-x + 36 = 3x.
  3. Solve for x: Now, solve for x. Add xx to both sides of the equation to get all xx terms on one side.\newlinex+36+x=3x+x-x + 36 + x = 3x + x\newline36=4x36 = 4x
  4. Divide to Find x: Divide both sides by 44 to solve for x.\newline36÷4=4x÷436 \div 4 = 4x \div 4\newline9=x9 = x
  5. Substitute xx back into First Equation: Now that we have the value of xx, we can substitute it back into the first equation to find the value of yy.\newliney=x+36y = -x + 36\newliney=9+36y = -9 + 36
  6. Calculate y Value: Calculate the value of y.\newliney=27y = 27
  7. Final Solution: We have found the values of xx and yy that solve the system of equations.\newlineThe solution is (9,27)(9, 27).

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