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Solve the system by substitution. {:[y=-9x+35],[y=-2x]:} (◻,◻)

Solve the system by substitution.\newliney=−9x+35y=−2x \begin{array}{l} y=-9 x+35 \\ y=-2 x \end{array} \newline(□,□) (\square, \square)

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Q. Solve the system by substitution.\newliney=−9x+35y=−2x \begin{array}{l} y=-9 x+35 \\ y=-2 x \end{array} \newline(□,□) (\square, \square)
  1. Identify Equation for Substitution: Identify the first equation to use for substitution.\newlineWe have two equations:\newline11) y=−9x+35y = -9x + 35\newline22) y=−2xy = -2x\newlineSince both equations are already solved for yy, we can set them equal to each other for substitution.
  2. Set Equations Equal and Solve: Set the two equations equal to each other and solve for xx.−9x+35=−2x-9x + 35 = -2xNow, we will solve for xx by moving all xx terms to one side of the equation.−9x+9x=−2x+9x+35-9x + 9x = -2x + 9x + 350x=7x+350x = 7x + 35

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