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Solve the system by substitution.

{:[y=9x+15],[y=4x]:}

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Solve the system by substitution.\newliney=9x+15y=4x \begin{array}{l} y=9 x+15 \\ y=4 x \end{array} \newline(,) (\square, \square)

Full solution

Q. Solve the system by substitution.\newliney=9x+15y=4x \begin{array}{l} y=9 x+15 \\ y=4 x \end{array} \newline(,) (\square, \square)
  1. Identify Equations to Solve: Identify the equations to be solved by substitution.\newlineWe have the system of equations:\newliney=9x+15y = 9x + 15\newliney=4xy = 4x\newlineWe will substitute the expression for yy from the second equation into the first equation.
  2. Substitute Expression for y: Substitute the expression for y from the second equation into the first equation.\newline9x+15=4x9x + 15 = 4x\newlineNow we will solve for xx.
  3. Solve for x: Solve for x.\newlineSubtract 4x4x from both sides of the equation to isolate terms with xx on one side.\newline9x+154x=4x4x9x + 15 - 4x = 4x - 4x\newline5x+15=05x + 15 = 0\newlineNow subtract 1515 from both sides to solve for xx.\newline5x=155x = -15\newlineDivide both sides by 55 to find the value of xx.\newlinex=15/5x = -15 / 5\newlinexx00
  4. Substitute Value of xx: Substitute the value of xx back into one of the original equations to solve for yy. We can use the second equation y=4xy = 4x. Substitute 3-3 for xx in the equation. y=4(3)y = 4(-3) y=12y = -12
  5. Write Solution as Ordered Pair: Write the solution as an ordered pair (x,y)(x, y). The solution is (3,12)(-3, -12).

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