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Solve the system by substitution. {:[y=8x],[y=2x-12]:} (◻,◻)

Solve the system by substitution.\newliney=8xy=2x−12 \begin{array}{l} y=8 x \\ y=2 x-12 \end{array} \newline(□,□) (\square, \square)

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Q. Solve the system by substitution.\newliney=8xy=2x−12 \begin{array}{l} y=8 x \\ y=2 x-12 \end{array} \newline(□,□) (\square, \square)
  1. Substitute Equations: Substitute the first equation y=8xy = 8x into the second equation y=2x−12y = 2x - 12.y=8xy = 8xy=2x−12y = 2x - 128x=2x−128x = 2x - 12
  2. Isolate x: Isolate x by subtracting 2x2x from both sides of the equation.\newline8x−2x=2x−2x−128x - 2x = 2x - 2x - 12\newline6x=−126x = -12
  3. Divide by 66: Divide both sides of the equation by 66 to solve for xx.6x6=−126\frac{6x}{6} = \frac{-12}{6}x=−2x = -2
  4. Substitute xx into yy: Substitute x=−2x = -2 into the first equation y=8xy = 8x to solve for yy.
    y=8(−2)y = 8(-2)
    y=−16y = -16

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