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Solve the system by substitution.

{:[y=-8x+18],[y=10 x]:}

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Solve the system by substitution.\newliney=8x+18y=10x \begin{array}{l} y=-8 x+18 \\ y=10 x \end{array} \newline(,) (\square, \square)

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Q. Solve the system by substitution.\newliney=8x+18y=10x \begin{array}{l} y=-8 x+18 \\ y=10 x \end{array} \newline(,) (\square, \square)
  1. Identify Equations: Identify the equations to be solved by substitution.\newlineWe have the system of equations:\newliney=8x+18y = -8x + 18\newliney=10xy = 10x\newlineWe will substitute the expression for yy from the first equation into the second equation.
  2. Substitute Expression: Substitute the expression for yy from the first equation into the second equation.\newlineSince y=8x+18y = -8x + 18, we can replace yy in the second equation with 8x+18-8x + 18.\newlineSo, 8x+18=10x-8x + 18 = 10x
  3. Solve for x: Solve for x.\newlineAdd 8x8x to both sides of the equation to get all xx terms on one side:\newline8x+18+8x=10x+8x-8x + 18 + 8x = 10x + 8x\newline18=18x18 = 18x\newlineNow, divide both sides by 1818 to solve for xx:\newline18/18=18x/1818 / 18 = 18x / 18\newline1=x1 = x
  4. Substitute Value for y: Substitute the value of xx back into one of the original equations to solve for yy. We can use the first equation y=8x+18y = -8x + 18. Substitute x=1x = 1 into this equation: y=8(1)+18y = -8(1) + 18 y=8+18y = -8 + 18 y=10y = 10
  5. Write Ordered Pair: Write the solution as an ordered pair (x,y)(x, y). The solution is (1,10)(1, 10).

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