Solve the system by substitution. {:[y=7x-13],[y=-6x]:} (◻,◻)

Set Equations Equal: Since both equations are equal to y, set them equal to each other to find x. 7x - 13 = -6xCombine Like Terms: Add 6x to both sides to get all x terms on one side. 7x + 6x - 13 = -6x + 6x 13x - 13 = 0Isolate x Term: Add 13 to both sides to isolate the x term. 13x - 13 + 13 = 0 + 13 13x = 13Solve for x: Divide both sides by 13 to solve for x. 13x / 13 = 13 / 13 x = 1Find y Value: Substitute x = 1 into one of the original equations to find y. We can use y = 7x - 13. y = 7(1) - 13 y = 7 - 13 y = -6Write Ordered Pair: Write the solution as an ordered pair (x, y). The solution is (1, -6).

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve the system by substitution.

{:[y=7x-13],[y=-6x]:}

(◻,◻)

Solve the system by substitution. $\newline$ $\begin{array}{l} y=7 x-13 \\ y=-6 x \end{array}$ $\newline$ $(\square, \square)$

View step-by-step help

Home

Math Problems

Algebra 2

Solve a system of equations in three variables using substitution

Full solution

Q. Solve the system by substitution.

\newline

\begin{array}{l} y=7 x-13 \\ y=-6 x \end{array}

\newline

(\square, \square)

Set Equations Equal: Since both equations are equal to $y$ , set them equal to each other to find $x$ . $7x - 13 = -6x$
Combine Like Terms: Add $6x$ to both sides to get all $x$ terms on one side. $\newline$ $7x + 6x - 13 = -6x + 6x$ $\newline$ $13x - 13 = 0$
Isolate x Term: Add $13$ to both sides to isolate the x term. $\newline$ $13x - 13 + 13 = 0 + 13$ $\newline$ $13x = 13$
Solve for x: Divide both sides by $13$ to solve for x. $\newline$ $\frac{13x}{13} = \frac{13}{13}$ $\newline$ $x = 1$
Find y Value: Substitute $x = 1$ into one of the original equations to find $y$ . We can use $y = 7x - 13$ .
$y = 7(1) - 13$
$y = 7 - 13$
$y = -6$
Write Ordered Pair: Write the solution as an ordered pair $(x, y)$ . $\newline$ The solution is $(1, -6)$ .