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Solve the system by substitution.

{:[y=-6x],[y=-5x+3]:}

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Solve the system by substitution.\newliney=6xy=5x+3 \begin{array}{l} y=-6 x \\ y=-5 x+3 \end{array} \newline(,) (\square, \square)

Full solution

Q. Solve the system by substitution.\newliney=6xy=5x+3 \begin{array}{l} y=-6 x \\ y=-5 x+3 \end{array} \newline(,) (\square, \square)
  1. Identify Equations for Substitution: Identify the first equation to use for substitution.\newlineWe have two equations:\newline11. y=6xy = -6x\newline22. y=5x+3y = -5x + 3\newlineWe can substitute the expression for yy from the first equation into the second equation.
  2. Substitute yy into Second Equation: Substitute y=6xy = -6x into the second equation y=5x+3y = -5x + 3.
    6x=5x+3-6x = -5x + 3
    Now, we need to solve for xx.
  3. Solve for x: Solve for x.\newlineAdd 5x5x to both sides of the equation to isolate xx on one side.\newline6x+5x=3-6x + 5x = 3\newlinex=3-x = 3\newlineNow, divide both sides by 1-1 to solve for xx.\newlinex=3x = -3
  4. Substitute xx back into First Equation: Substitute x=3x = -3 back into the first equation to solve for yy.\newliney=6xy = -6x\newliney=6(3)y = -6(-3)\newlineNow, calculate the value of yy.\newliney=18y = 18
  5. Write Solution as Ordered Pair: Write the solution as an ordered pair (x,y)(x, y). The solution is (3,18)(-3, 18).

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