Solve the system by substitution. {:[y=-4x],[y=-x-15]:} (◻,◻)

Identify Equations: Identify the two equations given in the system. The system of equations is: y = -4x y = -x - 15Set Equations Equal: Since both equations are already solved for y, set them equal to each other to find x. -4x = -x - 15Solve for x: Solve for x by adding 4x to both sides of the equation. -4x + 4x = -x + 4x - 15 0 = 3x - 15Isolate x Term: Add 15 to both sides of the equation to isolate the term with x. 3x - 15 + 15 = 0 + 15 3x = 15Divide by 3: Divide both sides by 3 to solve for x. 3x / 3 = 15 / 3 x = 5Substitute x: Substitute x = 5 into one of the original equations to solve for y. Using y = -4x: y = -4(5) y = -20Write Ordered Pair: Write the solution as an ordered pair (x, y). The solution is (5, -20).

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Solve the system by substitution.

{:[y=-4x],[y=-x-15]:}

(◻,◻)

Solve the system by substitution. $\newline$ $\begin{array}{l} y=-4 x \\ y=-x-15 \end{array}$ $\newline$ $(\square, \square)$

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Algebra 2

Solve a system of equations in three variables using substitution

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Q. Solve the system by substitution.

\newline

\begin{array}{l} y=-4 x \\ y=-x-15 \end{array}

\newline

(\square, \square)

Identify Equations: Identify the two equations given in the system. $\newline$ The system of equations is: $\newline$ $y = -4x$ $\newline$ $y = -x - 15$
Set Equations Equal: Since both equations are already solved for $y$ , set them equal to each other to find $x$ . $-4x = -x - 15$
Solve for x: Solve for x by adding $4x$ to both sides of the equation. $\newline$ $-4x + 4x = -x + 4x - 15$ $\newline$ $0 = 3x - 15$
Isolate x Term: Add $15$ to both sides of the equation to isolate the term with $x$ . $\newline$ $3x - 15 + 15 = 0 + 15$ $\newline$ $3x = 15$
Divide by $3$ : Divide both sides by $3$ to solve for $x$ . $\frac{3x}{3} = \frac{15}{3}$ $x = 5$
Substitute $x$ : Substitute $x = 5$ into one of the original equations to solve for $y$ . Using $y = -4x$ : $y = -4(5)$ $y = -20$
Write Ordered Pair: Write the solution as an ordered pair $(x, y)$ . $\newline$ The solution is $(5, -20)$ .