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Solve the system by substitution.

{:[y=-4x+42],[y=3x]:}

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Solve the system by substitution.\newliney=4x+42y=3x \begin{array}{l} y=-4 x+42 \\ y=3 x \end{array} \newline(,) (\square, \square)

Full solution

Q. Solve the system by substitution.\newliney=4x+42y=3x \begin{array}{l} y=-4 x+42 \\ y=3 x \end{array} \newline(,) (\square, \square)
  1. Identify Equations for Substitution: Identify the first equation to use for substitution.\newlineWe have two equations:\newline11) y=4x+42y = -4x + 42\newline22) y=3xy = 3x\newlineWe can substitute the expression for yy from the second equation into the first equation.
  2. Substitute yy into First Equation: Substitute y=3xy = 3x into the first equation y=4x+42y = -4x + 42.\newline4x+42=3x-4x + 42 = 3x
  3. Solve for x: Solve for x.\newlineAdd 4x4x to both sides of the equation to get all xx terms on one side.\newline4x+4x+42=3x+4x-4x + 4x + 42 = 3x + 4x\newline42=7x42 = 7x
  4. Find Value of x: Divide both sides by 77 to find the value of xx.427=7x7\frac{42}{7} = \frac{7x}{7}x=6x = 6
  5. Substitute xx into Second Equation: Substitute x=6x = 6 into the second equation y=3xy = 3x to find the value of yy.\newliney=3×6y = 3 \times 6\newliney=18y = 18
  6. Write Solution as Ordered Pair: Write the solution as an ordered pair (x,y)(x, y). The solution is (6,18)(6, 18).

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