Solve the system by substitution. {:[y=3x],[y=4x+10]:} (◻,◻)

Given Equations: We are given two equations y = 3x and y = 4x + 10. We will substitute the expression for y from the first equation into the second equation.Substitute and Simplify: Substitute y = 3x into y = 4x + 10. 3x = 4x + 10Solve for x: Solve for x by subtracting 3x from both sides of the equation. 3x - 3x = 4x + 10 - 3x 0 = x + 10Find y: Subtract 10 from both sides to find the value of x. 0 - 10 = x + 10 - 10 -10 = xFinal Solution: Now that we have the value of x, we can substitute it back into either of the original equations to find y. We'll use y = 3x. y = 3(-10)Multiply 3 by -10 to get the value of y. y = -30We have found the values of x and y. The solution to the system of equations is x = -10 and y = -30.

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Solve the system by substitution.

{:[y=3x],[y=4x+10]:}

(◻,◻)

Solve the system by substitution. $\newline$ $\begin{array}{l} y=3 x \\ y=4 x+10 \end{array}$ $\newline$ $(\square, \square)$

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Algebra 2

Solve a system of equations in three variables using substitution

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Q. Solve the system by substitution.

\newline

\begin{array}{l} y=3 x \\ y=4 x+10 \end{array}

\newline

(\square, \square)

Given Equations: We are given two equations $y = 3x$ and $y = 4x + 10$ . We will substitute the expression for $y$ from the first equation into the second equation.
Substitute and Simplify: Substitute $y = 3x$ into $y = 4x + 10$ . $3x = 4x + 10$
Solve for x: Solve for x by subtracting $3x$ from both sides of the equation. $\newline$ $3x - 3x = 4x + 10 - 3x$ $\newline$ $0 = x + 10$
Find $y$ : Subtract $10$ from both sides to find the value of $x$ . $0 - 10 = x + 10 - 10$ $-10 = x$
Final Solution: Now that we have the value of $x$ , we can substitute it back into either of the original equations to find $y$ . We'll use $y = 3x$ . $\newline$ $y = 3(-10)$
Final Solution: Now that we have the value of $x$ , we can substitute it back into either of the original equations to find $y$ . We'll use $y = 3x$ . $\newline$ $y = 3(-10)$ Multiply $3$ by $-10$ to get the value of $y$ . $\newline$ $y = -30$
Final Solution: Now that we have the value of $x$ , we can substitute it back into either of the original equations to find $y$ . We'll use $y = 3x$ . $y = 3(-10)$ Multiply $3$ by $-10$ to get the value of $y$ . $y = -30$ We have found the values of $x$ and $y$ . The solution to the system of equations is $y$ $0$ and $y = -30$ .