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Solve the system by substitution.

{:[y=-2x],[y=-6x+12]:}

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Solve the system by substitution.\newliney=2xy=6x+12 \begin{array}{l} y=-2 x \\ y=-6 x+12 \end{array} \newline(,) (\square, \square)

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Q. Solve the system by substitution.\newliney=2xy=6x+12 \begin{array}{l} y=-2 x \\ y=-6 x+12 \end{array} \newline(,) (\square, \square)
  1. Identify Equations: Identify the two equations given in the system.\newlineThe system of equations is:\newliney=2xy = -2x\newliney=6x+12y = -6x + 12
  2. Set Equations Equal: Since both equations are already solved for yy, we can set them equal to each other to find the value of xx.2x=6x+12-2x = -6x + 12
  3. Add and Isolate Terms: Add 6x6x to both sides of the equation to isolate terms with xx on one side.\newline2x+6x=6x+6x+12-2x + 6x = -6x + 6x + 12\newline4x=124x = 12
  4. Solve for x: Divide both sides of the equation by 44 to solve for x.\newline4x4=124\frac{4x}{4} = \frac{12}{4}\newlinex=3x = 3
  5. Substitute and Solve for yy: Substitute the value of xx back into one of the original equations to solve for yy. We can use y=2xy = -2x.\newliney=2(3)y = -2(3)\newliney=6y = -6
  6. Write Ordered Pair: Write the solution as an ordered pair (x,y)(x, y).\newlineThe solution is (3,6)(3, -6).

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