Solve the system by substitution. {:[y=-2x-50],[y=8x]:} (◻,◻)

Identify Equations: Identify the two equations given in the system. The system of equations is: y = -2x - 50 y = 8xSet Equations Equal: Since both equations are already solved for y, set them equal to each other to find the value of x. -2x - 50 = 8xCombine Like Terms: Combine like terms to solve for x. -2x - 8x = 50 -10x = 50Solve for x: Divide both sides by -10 to find the value of x. x = 50 / -10 x = -5Substitute for y: Substitute the value of x into one of the original equations to find the value of y. Using y = -2x - 50, substitute x = -5: y = -2(-5) - 50 y = 10 - 50 y = -40Write Ordered Pair: Write the solution as an ordered pair (x, y). The solution is (-5, -40).

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Solve the system by substitution.

{:[y=-2x-50],[y=8x]:}

(◻,◻)

Solve the system by substitution. $\newline$ $\begin{array}{l} y=-2 x-50 \\ y=8 x \end{array}$ $\newline$ $(\square, \square)$

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Algebra 2

Solve a system of equations in three variables using substitution

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Q. Solve the system by substitution.

\newline

\begin{array}{l} y=-2 x-50 \\ y=8 x \end{array}

\newline

(\square, \square)

Identify Equations: Identify the two equations given in the system. $\newline$ The system of equations is: $\newline$ $y = -2x - 50$ $\newline$ $y = 8x$
Set Equations Equal: Since both equations are already solved for $y$ , set them equal to each other to find the value of $x$ . $-2x - 50 = 8x$
Combine Like Terms: Combine like terms to solve for $x$ . $-2x - 8x = 50$ $-10x = 50$
Solve for x: Divide both sides by $-10$ to find the value of x. $\newline$ $x = \frac{50}{-10}$ $\newline$ $x = -5$
Substitute for $y$ : Substitute the value of $x$ into one of the original equations to find the value of $y$ . Using $y = -2x - 50$ , substitute $x = -5$ : $y = -2(-5) - 50$ $y = 10 - 50$ $y = -40$
Write Ordered Pair: Write the solution as an ordered pair $(x, y)$ . $\newline$ The solution is $(-5, -40)$ .