Solve the system by substitution. {:[y=2x-48],[y=-6x]:} (◻,◻)

Identify Equations: Identify the equations to be solved by substitution. We have the system of equations: y = 2x - 48 y = -6x We will substitute the expression for y from the first equation into the second equation.Substitute Expression: Substitute the expression for y from the first equation into the second equation. Since y = 2x - 48, we can replace y in the second equation with 2x - 48: 2x - 48 = -6xSolve for x: Solve for x. Add 6x to both sides of the equation to get all x terms on one side: 2x - 48 + 6x = -6x + 6x 8x - 48 = 0Isolate x: Isolate x. Add 48 to both sides of the equation: 8x - 48 + 48 = 0 + 48 8x = 48Divide for x: Divide both sides by 8 to find the value of x. 8x / 8 = 48 / 8 x = 6Substitute for y: Substitute the value of x back into one of the original equations to find y. We can use the first equation y = 2x - 48: y = 2(6) - 48 y = 12 - 48 y = -36Write Ordered Pair: Write the solution as an ordered pair (x, y). The solution is (6, -36).

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Solve the system by substitution.

{:[y=2x-48],[y=-6x]:}

(◻,◻)

Solve the system by substitution. $\newline$ $\begin{array}{l} y=2 x-48 \\ y=-6 x \end{array}$ $\newline$ $(\square, \square)$

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Algebra 2

Solve a system of equations in three variables using substitution

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Q. Solve the system by substitution.

\newline

\begin{array}{l} y=2 x-48 \\ y=-6 x \end{array}

\newline

(\square, \square)

Identify Equations: Identify the equations to be solved by substitution. $\newline$ We have the system of equations: $\newline$ $y = 2x - 48$ $\newline$ $y = -6x$ $\newline$ We will substitute the expression for $y$ from the first equation into the second equation.
Substitute Expression: Substitute the expression for $y$ from the first equation into the second equation. $\newline$ Since $y = 2x - 48$ , we can replace $y$ in the second equation with $2x - 48$ : $\newline$ $2x - 48 = -6x$
Solve for x: Solve for x. $\newline$ Add $6x$ to both sides of the equation to get all $x$ terms on one side: $\newline$ $2x - 48 + 6x = -6x + 6x$ $\newline$ $8x - 48 = 0$
Isolate x: Isolate $x$ . Add $48$ to both sides of the equation: $8x - 48 + 48 = 0 + 48$ $8x = 48$
Divide for $x$ : Divide both sides by $8$ to find the value of $x$ . $\frac{8x}{8} = \frac{48}{8}$ $x = 6$
Substitute for y: Substitute the value of $x$ back into one of the original equations to find $y$ . We can use the first equation $y = 2x - 48$ : $y = 2(6) - 48$ $y = 12 - 48$ $y = -36$
Write Ordered Pair: Write the solution as an ordered pair $(x, y)$ . $\newline$ The solution is $(6, -36)$ .