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Solve the system by substitution.

{:[-x=y],[-6x-2y=20]:}

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Solve the system by substitution.\newlinexamp;=y6x2yamp;=20 \begin{aligned} -x & =y \\ -6 x-2 y & =20 \end{aligned} \newline(,) (\square, \square)

Full solution

Q. Solve the system by substitution.\newlinex=y6x2y=20 \begin{aligned} -x & =y \\ -6 x-2 y & =20 \end{aligned} \newline(,) (\square, \square)
  1. Identify Equation for Substitution: Identify the first equation to use for substitution.\newlineThe first equation is x=y-x = y. This equation can be used to express yy in terms of xx.
  2. Substitute in Second Equation: Substitute x-x for yy in the second equation.\newlineThe second equation is 6x2y=20-6x - 2y = 20. Substituting x-x for yy, we get 6x2(x)=20-6x - 2(-x) = 20.
  3. Simplify and Solve for x: Simplify the equation and solve for xx. Simplifying the equation, we have 6x+2x=20-6x + 2x = 20, which simplifies to 4x=20-4x = 20. Dividing both sides by 4-4, we find x=5x = -5.
  4. Substitute xx into First Equation: Substitute xx back into the first equation to find yy. Using the first equation x=y-x = y and substituting x=5x = -5, we get (5)=y-(-5) = y, which simplifies to y=5y = 5.
  5. Write Solution as Ordered Pair: Write the solution as an ordered pair (x,y)(x, y). The solution to the system of equations is (5,5)(-5, 5).

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