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Solve the system by substitution.

{:[-x-3y=-35],[2x=y]:}

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Solve the system by substitution.\newlinex3yamp;=352xamp;=y \begin{aligned} -x-3 y & =-35 \\ 2 x & =y \end{aligned} \newline(,) (\square, \square)

Full solution

Q. Solve the system by substitution.\newlinex3y=352x=y \begin{aligned} -x-3 y & =-35 \\ 2 x & =y \end{aligned} \newline(,) (\square, \square)
  1. Identify easier equation: Identify the easier equation to substitute from. In this case, the second equation 2x=y2x = y is easier to use for substitution because it can be directly solved for yy.
  2. Solve for y: Solve the second equation for y. We have 2x=y2x = y, so y=2xy = 2x.
  3. Substitute into first equation: Substitute y=2xy = 2x into the first equation x3y=35-x - 3y = -35. This gives us x3(2x)=35-x - 3(2x) = -35.
  4. Simplify and solve for x: Simplify and solve for x. The equation becomes x6x=35-x - 6x = -35, which simplifies to 7x=35-7x = -35.
  5. Divide by 7-7: Divide both sides of the equation by 7-7 to find the value of xx. This gives us x=(35)/(7)x = (-35)/(-7), so x=5x = 5.
  6. Substitute xx back in: Substitute x=5x = 5 back into the equation y=2xy = 2x to find the value of yy. This gives us y=2(5)y = 2(5), so y=10y = 10.
  7. Write solution as ordered pair: Write the solution as an ordered pair (x,y)(x, y). The solution is (5,10)(5, 10).

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