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Solve the system by substitution.

{:[-6x+4y=38],[x=7y]:}

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Solve the system by substitution.\newline6x+4yamp;=38xamp;=7y \begin{aligned} -6 x+4 y & =38 \\ x & =7 y \end{aligned} \newline(,) (\square, \square)

Full solution

Q. Solve the system by substitution.\newline6x+4y=38x=7y \begin{aligned} -6 x+4 y & =38 \\ x & =7 y \end{aligned} \newline(,) (\square, \square)
  1. Identify Equation for Substitution: Identify the equation that can be used for substitution.\newlineIn the given system of equations, we have:\newline6x+4y=38-6x + 4y = 38\newlinex=7yx = 7y\newlineThe second equation, x=7yx = 7y, can be directly used for substitution because xx is already isolated.
  2. Substitute xx into First Equation: Substitute x=7yx = 7y into the first equation.\newlineReplace xx in the first equation with 7y7y:\newline6(7y)+4y=38-6(7y) + 4y = 38
  3. Simplify and Solve for y: Simplify the equation and solve for yy.
    42y+4y=38-42y + 4y = 38
    38y=38-38y = 38
    Divide both sides by 38-38 to find yy:
    y=3838y = \frac{38}{-38}
    y=1y = -1
  4. Substitute yy back into xx: Substitute y=1y = -1 back into the equation x=7yx = 7y to find xx.x=7(1)x = 7(-1)x=7x = -7
  5. Write Solution as Ordered Pair: Write the solution as an ordered pair (x,y)(x, y). The solution to the system of equations is (7,1)(-7, -1).

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