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Solve the system by substitution.

{:[3y=x],[3x-4y=-25]:}

Solve the system by substitution.\newline3yamp;=x3x4yamp;=25 \begin{aligned} 3 y & =x \\ 3 x-4 y & =-25 \end{aligned}

Full solution

Q. Solve the system by substitution.\newline3y=x3x4y=25 \begin{aligned} 3 y & =x \\ 3 x-4 y & =-25 \end{aligned}
  1. Identify Equation for Substitution: Identify the first equation to use for substitution.\newlineThe first equation is 3y=x3y = x. We can use this to substitute for xx in the second equation.
  2. Substitute in Second Equation: Substitute 3y3y for xx in the second equation.\newlineThe second equation is 3x4y=253x - 4y = -25. Substituting 3y3y for xx gives us 3(3y)4y=253(3y) - 4y = -25.
  3. Simplify and Solve for y: Simplify the equation and solve for y. 3(3y)4y=253(3y) - 4y = -25 simplifies to 9y4y=259y - 4y = -25, which further simplifies to 5y=255y = -25.
  4. Divide to Find y Value: Divide both sides by 55 to find the value of yy.5y=255y = -25 divided by 55 gives y=5y = -5.
  5. Substitute yy back for xx: Substitute y=5y = -5 back into the first equation to find xx. The first equation is 3y=x3y = x. Substituting 5-5 for yy gives us 3(5)=x3(-5) = x.
  6. Calculate x Value: Calculate the value of x.\newline3(5)=x3(-5) = x simplifies to 15=x-15 = x. So, x=15x = -15.

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