Solve the system by substitution. {:[-2y=x],[x+8y=-6]:} (◻,◻)

Identify Equation for Substitution: Identify the first equation to use for substitution. The first equation is -2y = x. We can use this to substitute for x in the second equation.Substitute in Second Equation: Substitute -2y for x in the second equation x + 8y = -6. Substituting we get -2y + 8y = -6.Solve for y: Solve for y. Combining like terms we get 6y = -6. Divide both sides by 6 to get y = -1.Substitute for x: Substitute y = -1 into the first equation -2y = x to find x. Substituting we get -2(-1) = x.Solve for x: Solve for x. Multiplying we get x = 2.Write Ordered Pair Solution: Write the solution as an ordered pair (x, y). The solution is (2, -1).

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Solve the system by substitution.

{:[-2y=x],[x+8y=-6]:}

(◻,◻)

Solve the system by substitution. $\newline$ $\begin{aligned} -2 y & =x \\ x+8 y & =-6 \end{aligned}$ $\newline$ $(\square, \square)$

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Algebra 2

Solve a system of equations in three variables using substitution

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Q. Solve the system by substitution.

\newline

\begin{aligned} -2 y & =x \\ x+8 y & =-6 \end{aligned}

\newline

(\square, \square)

Identify Equation for Substitution: Identify the first equation to use for substitution. $\newline$ The first equation is $-2y = x$ . We can use this to substitute for $x$ in the second equation.
Substitute in Second Equation: Substitute $-2y$ for $x$ in the second equation $x + 8y = -6$ . Substituting we get $-2y + 8y = -6$ .
Solve for y: Solve for y. $\newline$ Combining like terms we get $6y = -6$ . $\newline$ Divide both sides by $6$ to get $y = -1$ .
Substitute for $x$ : Substitute $y = -1$ into the first equation $-2y = x$ to find $x$ . $\newline$ Substituting we get $-2(-1) = x$ .
Solve for x: Solve for x. $\newline$ Multiplying we get $x = 2$ .
Write Ordered Pair Solution: Write the solution as an ordered pair $(x, y)$ . $\newline$ The solution is $(2, -1)$ .