Solve the system by substitution. {:[2x+8y=28],[x=10 y]:} (◻,◻)

Identify Equation: Identify the equation that can be used for substitution. In the given system of equations, the second equation directly gives the value of x in terms of y. We can use this to substitute into the first equation.Substitute x: Substitute x = 10y into the first equation 2x + 8y = 28. 2(10y) + 8y = 28 20y + 8y = 28 28y = 28Solve for y: Solve for y. Divide both sides of the equation by 28. 28y / 28 = 28 / 28 y = 1Substitute y: Substitute y = 1 into the second equation x = 10y to find x. x = 10(1) x = 10Write Solution: Write the solution as an ordered pair (x, y). The solution is (10, 1).

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Solve the system by substitution.

{:[2x+8y=28],[x=10 y]:}

(◻,◻)

Solve the system by substitution. $\newline$ $\begin{aligned} 2 x+8 y & =28 \\ x & =10 y \end{aligned}$ $\newline$ $(\square, \square)$

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Algebra 2

Solve a system of equations in three variables using substitution

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Q. Solve the system by substitution.

\newline

\begin{aligned} 2 x+8 y & =28 \\ x & =10 y \end{aligned}

\newline

(\square, \square)

Identify Equation: Identify the equation that can be used for substitution. $\newline$ In the given system of equations, the second equation directly gives the value of $x$ in terms of $y$ . We can use this to substitute into the first equation.
Substitute x: Substitute $x = 10y$ into the first equation $2x + 8y = 28$ . $\newline$ $2(10y) + 8y = 28$ $\newline$ $20y + 8y = 28$ $\newline$ $28y = 28$
Solve for y: Solve for y. $\newline$ Divide both sides of the equation by $28$ . $\newline$ $\frac{28y}{28} = \frac{28}{28}$ $\newline$ $y = 1$
Substitute $y$ : Substitute $y = 1$ into the second equation $x = 10y$ to find $x$ . $\newline$ $x = 10(1)$ $\newline$ $x = 10$
Write Solution: Write the solution as an ordered pair $(x, y)$ . The solution is $(10, 1)$ .