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Solve the system by substitution. {:[-2x+7y=-40],[y=x]:} (◻,◻)

Solve the system by substitution.\newline−2x+7yamp;=−40yamp;=x \begin{aligned} -2 x+7 y & =-40 \\ y & =x \end{aligned} \newline(□,□) (\square, \square)

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Q. Solve the system by substitution.\newline−2x+7y=−40y=x \begin{aligned} -2 x+7 y & =-40 \\ y & =x \end{aligned} \newline(□,□) (\square, \square)
  1. Identify Equation: Identify the equation that can be easily substituted.\newlineIn the given system of equations, the second equation y=xy = x is already solved for yy, which makes it easy to substitute into the first equation.
  2. Substitute y=xy = x: Substitute y=xy = x into the first equation −2x+7y=−40-2x + 7y = -40.
    −2x+7(x)=−40-2x + 7(x) = -40
    −2x+7x=−40-2x + 7x = -40
    5x=−405x = -40
  3. Solve for x: Solve for x.\newlineDivide both sides of the equation by 55 to find the value of xx.\newline5x5=−405\frac{5x}{5} = \frac{-40}{5}\newlinex=−8x = -8
  4. Substitute x=−8x = -8: Substitute x=−8x = -8 into the second equation y=xy = x to find the value of yy.\newliney=−8y = -8
  5. Write Ordered Pair: Write the solution as an ordered pair (x,y)(x, y).\newlineThe solution is (−8,−8)(-8, -8).

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