Solve for z. z + 13 > 12 or z + 19 ≤ 7 Write your answer as a compound inequality with integers. Choices: (A)-1 > z ≥ -12 (B)-1 ≥ z ≥ -12 (C)z ≥ -1 or z ≤ -12 (D)z > -1 or z ≤ -12

First Inequality Solution: We have two inequalities to solve: z + 13 > 12 and z + 19 ≤ 7. Let's start with the first inequality z + 13 > 12. To isolate z, we need to subtract 13 from both sides of the inequality. z + 13 - 13 > 12 - 13 z > -1Second Inequality Solution: Now let's solve the second inequality z + 19 ≤ 7. To isolate z, we need to subtract 19 from both sides of the inequality. z + 19 - 19 ≤ 7 - 19 z ≤ -12Combining Inequalities: We now have two parts of the compound inequality: z > -1 and z ≤ -12. Since the original statement uses ＂or,＂ we combine these two inequalities using ＂or.＂ z > -1 or z ≤ -12

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Solve for $z$ . $\newline$ z + 13 > 12 or $z + 19 \leq 7$ $\newline$ Write your answer as a compound inequality with integers. $\newline$ Choices: $\newline$ (A)-1 > z \geq -12 $\newline$ (B) $-1 \geq z \geq -12$ $\newline$ (C) $z \geq -1$ or $z \leq -12$ $\newline$ (D)z > -1 or $z \leq -12$

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Math Problems

Algebra 1

Solve compound inequalities

Full solution

Q. Solve for

z

\newline

z + 13 > 12

z + 19 \leq 7

\newline

Write your answer as a compound inequality with integers.

\newline

Choices:

\newline

(A)

-1 > z \geq -12

\newline

(B)

-1 \geq z \geq -12

\newline

(C)

z \geq -1

z \leq -12

\newline

(D)

z > -1

z \leq -12

First Inequality Solution: We have two inequalities to solve: z + 13 > 12 and $z + 19 \leq 7$ . Let's start with the first inequality z + 13 > 12. $\newline$ To isolate $z$ , we need to subtract $13$ from both sides of the inequality. $\newline$ z + 13 - 13 > 12 - 13 $\newline$ z > -1
Second Inequality Solution: Now let's solve the second inequality $z + 19 \leq 7$ . $\newline$ To isolate $z$ , we need to subtract $19$ from both sides of the inequality. $\newline$ $z + 19 - 19 \leq 7 - 19$ $\newline$ $z \leq -12$
Combining Inequalities: We now have two parts of the compound inequality: z > -1 and $z \leq -12$ . Since the original statement uses ＂or,＂ we combine these two inequalities using ＂or.＂ $\newline$ z > -1 or $z \leq -12$