Solve for x. -8x+44 = 60quad" AND "quad-4x+50 -2 (B) x

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Solve for x. -8x+44 >= 60quad" AND "quad-4x+50 < 58 Choose 1 answer: (A) x > -2 (B) x <= -2 (C) x=-2 (D) There are no solutions (E) All values of x are solutions

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Solve First Inequality: Solve the first inequality -8x + 44 ≥ 60. To isolate x, we need to subtract 44 from both sides of the inequality. -8x + 44 - 44 ≥ 60 - 44 -8x ≥ 16 Now, we divide both sides by -8. Remember that dividing by a negative number reverses the inequality sign. -8x / -8 ≤ 16 / -8 x ≤ -2Solve Second Inequality: Solve the second inequality -4x + 50 < 58. Similarly, we subtract 50 from both sides to isolate the -4x term. -4x + 50 - 50 < 58 - 50 -4x < 8 Now, we divide both sides by -4, again remembering to reverse the inequality sign. -4x / -4 > 8 / -4 x > -2Combine Solutions: Combine the solutions from Step 1 and Step 2. We have x ≤ -2 from the first inequality and x > -2 from the second inequality. These two inequalities contradict each other, as there is no number that is both greater than and less than or equal to -2 at the same time. Therefore, there are no solutions that satisfy both inequalities simultaneously.

Solve for $x$ . $\newline$ -8 x+44 \geq 60 \quad \text { AND } \quad-4 x+50<58 $\newline$ Choose $1$ answer: $\newline$ (A) x>-2 $\newline$ (B) $x \leq-2$ $\newline$ (C) $x=-2$ $\newline$ (D) There are no solutions $\newline$ (E) All values of $x$ are solutions

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Solve for x x x.\newline -8 x+44 \geq 60 \quad \text { AND } \quad-4 x+50<58 \newlineChoose 111 answer:\newline(A) x>-2 \newline(B) x≤−2 x \leq-2 x≤−2\newline(C) x=−2 x=-2 x=−2\newline(D) There are no solutions\newline(E) All values of x x x are solutions

Solve for $x$ . $\newline$ -8 x+44 \geq 60 \quad \text { AND } \quad-4 x+50<58 $\newline$ Choose $1$ answer: $\newline$ (A) x>-2 $\newline$ (B) $x \leq-2$ $\newline$ (C) $x=-2$ $\newline$ (D) There are no solutions $\newline$ (E) All values of $x$ are solutions