Solve for x. -8x+14 >= 60quad" OR "quad-4x+50 -2 (B) x -2 (D) There are no solutions (E) All values of x are solutions

Solve First Inequality: First, let's solve the inequality -8x + 14 >= 60. Subtract 14 from both sides to isolate the term with x. -8x + 14 - 14 >= 60 - 14 -8x >= 46 Now, divide both sides by -8. Remember that dividing by a negative number reverses the inequality sign. -8x / -8 8 / -4 x > -2Combine Inequalities: Now we have two inequalities from the compound inequality: x -2 These two inequalities represent the solution to the compound inequality.

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Solve for
x.

-8x+14 >= 60quad" OR "quad-4x+50 < 58
Choose 1 answer:
(A)
x <= -(23)/(4) or
x > -2
(B)
x <= -(23)/(4)
(C)
x > -2
(D) There are no solutions
(E) All values of
x are solutions

Solve for $x$ . $\newline$ -8 x+14 \geq 60 \quad \text { OR } \quad-4 x+50<58 $\newline$ Choose $1$ answer: $\newline$ (A) $x \leq-\frac{23}{4}$ or x>-2 $\newline$ (B) $x \leq-\frac{23}{4}$ $\newline$ (C) x>-2 $\newline$ (D) There are no solutions $\newline$ (E) All values of $x$ are solutions

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Math Problems

Algebra 1

Solve compound inequalities

Full solution

Q. Solve for

x

\newline

-8 x+14 \geq 60 \quad \text { OR } \quad-4 x+50<58

\newline

Choose

1

answer:

\newline

(A)

x \leq-\frac{23}{4}

x>-2

\newline

(B)

x \leq-\frac{23}{4}

\newline

(C)

x>-2

\newline

(D) There are no solutions

\newline

(E) All values of

x

are solutions

Solve First Inequality: First, let's solve the inequality $-8x + 14 \geq 60$ . $\newline$ Subtract $14$ from both sides to isolate the term with $x$ . $\newline$ $-8x + 14 - 14 \geq 60 - 14$ $\newline$ $-8x \geq 46$ $\newline$ Now, divide both sides by $-8$ . Remember that dividing by a negative number reverses the inequality sign. $\newline$ $-8x / -8 \leq 46 / -8$ $\newline$ x \leq - $46 / 8$ $\newline$ x \leq - $23 / 4$
Solve Second Inequality: Next, let's solve the inequality -4x + 50 < 58.
Subtract $50$ from both sides to isolate the term with $x$ .
-4x + 50 - 50 < 58 - 50
-4x < 8
Now, divide both sides by $-4$ . Again, remember that dividing by a negative number reverses the inequality sign.
\frac{-4x}{-4} > \frac{8}{-4}
x > -2
Combine Inequalities: Now we have two inequalities from the compound inequality: $\newline$ $x \leq -\frac{23}{4}$ or x > -2 $\newline$ These two inequalities represent the solution to the compound inequality.