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Solve for xx. \newline3x+10=253x+10 = 25 \newline x=x=\square

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Q. Solve for xx. \newline3x+10=253x+10 = 25 \newline x=x=\square
  1. Isolate variable term: Isolate the variable term by subtracting 1010 from both sides of the equation.\newline3x+1010=25103x + 10 - 10 = 25 - 10\newline3x=153x = 15
  2. Divide both sides: Divide both sides of the equation by 33 to solve for xx.\newline3x3=153\frac{3x}{3} = \frac{15}{3}\newlinex=5x = 5

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