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{:[2x^(2)-12 x+18=0],[x=]:}

Solve for x x .\newline2x212x+18=0x= \begin{array}{l} 2 x^{2}-12 x+18=0 \\ x= \end{array}

Full solution

Q. Solve for x x .\newline2x212x+18=0x= \begin{array}{l} 2 x^{2}-12 x+18=0 \\ x= \end{array}
  1. Factor Quadratic Equation: We are given the quadratic equation 2x212x+18=02x^2 - 12x + 18 = 0. The first step is to try to factor the quadratic, if possible. We look for two numbers that multiply to 2×182\times18 (which is 3636) and add up to 12-12.
  2. Identify Common Factors: We notice that the numbers 6-6 and 6-6 multiply to 3636 and add up to 12-12. So we can write the quadratic as 2x26x6x+18=02x^2 - 6x - 6x + 18 = 0.
  3. Factor by Grouping: Now we can factor by grouping. We group the terms as 2x26x2x^2 - 6x and 6x+18 -6x + 18 and factor out the common factors from each group.
  4. Simplify Factors: From the first group, we factor out 2x2x, and from the second group, we factor out 6-6. This gives us 2x(x3)6(x3)=02x(x - 3) - 6(x - 3) = 0.
  5. Apply Zero Product Property: Since both terms have a common factor of (x3)(x - 3), we can factor this out to get (2x6)(x3)=0(2x - 6)(x - 3) = 0.
  6. Set Factors Equal: We can simplify the first factor by dividing by 22, which gives us (x3)(x3)=0(x - 3)(x - 3) = 0 or (x3)2=0(x - 3)^2 = 0.
  7. Solve for xx: Now we can use the zero product property, which states that if a product of factors equals zero, then at least one of the factors must be zero. We set each factor equal to zero: x3=0x - 3 = 0.
  8. Solve for x: Now we can use the zero product property, which states that if a product of factors equals zero, then at least one of the factors must be zero. We set each factor equal to zero: x3=0x - 3 = 0.Solving for xx, we add 33 to both sides of the equation to get x=3x = 3.

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