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Solve for $u$ . $\newline$ $10 + 3u \leq 1$

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Solve two-step linear inequalities

Full solution

Q. Solve for

u

.

\newline

10 + 3u \leq 1

Isolate variable term: Isolate the variable term by subtracting $10$ from both sides. $\newline$ $10 + 3u - 10 \leq 1 - 10$ $\newline$ $3u \leq -9$
Divide both sides: Divide both sides by $3$ to solve for $u$ . $\frac{3u}{3} \leq \frac{-9}{3}$ $u \leq -3$

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