Solve for t. -11(t + 9) + 2 ≤ 13 ______

Distribute -11: Distribute -11 across the parentheses in the inequality -11(t + 9) + 2 ≤ 13. -11(t) + -11(9) + 2 ≤ 13 -11t - 99 + 2 ≤ 13Combine like terms: Combine like terms on the left side of the inequality. -11t - 97 ≤ 13Add 97: Add 97 to both sides of the inequality to isolate the term with the variable t. -11t - 97 + 97 ≤ 13 + 97 -11t ≤ 110Divide and reverse inequality: Divide both sides of the inequality by -11 to solve for t. Remember to reverse the inequality sign because we are dividing by a negative number. -11t / -11 ≥ 110 / -11 t ≥ -10

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Solve for $t$ . $\newline$ $-11(t + 9) + 2 \leq 13$

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Algebra 1

Solve advanced linear inequalities

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Q. Solve for

t

\newline

-11(t + 9) + 2 \leq 13

Distribute $-11$ : Distribute $-11$ across the parentheses in the inequality $-11(t + 9) + 2 \leq 13$ .
$-11(t) + -11(9) + 2 \leq 13$
$-11t - 99 + 2 \leq 13$
Combine like terms: Combine like terms on the left side of the inequality. $-11t - 97 \leq 13$
Add $97$ : Add $97$ to both sides of the inequality to isolate the term with the variable $t$ . $\newline$ $-11t - 97 + 97 \leq 13 + 97$ $\newline$ $-11t \leq 110$
Divide and reverse inequality: Divide both sides of the inequality by $-11$ to solve for $t$ . Remember to reverse the inequality sign because we are dividing by a negative number. $\newline$ $-11t / -11 \geq 110 / -11$ $\newline$ $t \geq -10$