Solve for s. s - 14 ≥ 3 or s - 17 17 or s 17 or s ≤ 14 (C)s ≥ 17 or s ≤ 14 (D)s ≥ 17 or s < 14

Isolate s by adding 14: To solve the first part of the compound inequality, s - 14 ≥ 3, we need to isolate s by adding 14 to both sides of the inequality. s - 14 + 14 ≥ 3 + 14 s ≥ 17Isolate s by adding 17: To solve the second part of the compound inequality, s - 17 < -3, we need to isolate s by adding 17 to both sides of the inequality. s - 17 + 17 < -3 + 17 s < 14Combine both parts: Now we combine both parts of the compound inequality using ＂or＂ as given in the original problem. s ≥ 17 or s < 14

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Math Problems

Algebra 1

Solve compound inequalities

Full solution

Q. Solve for

s

\newline

s - 14 \geq 3

s - 17 < -3

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Write your answer as a compound inequality with integers.

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Choices:

\newline

(A)

s > 17

s < 14

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(B)

s > 17

s \leq 14

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(C)

s \geq 17

s \leq 14

\newline

(D)

s \geq 17

s < 14

Isolate $s$ by adding $14$ : To solve the first part of the compound inequality, $s - 14 \geq 3$ , we need to isolate $s$ by adding $14$ to both sides of the inequality. $\newline$ $s - 14 + 14 \geq 3 + 14$ $\newline$ $s \geq 17$
Isolate $s$ by adding $17$ : To solve the second part of the compound inequality, s - 17 < -3, we need to isolate $s$ by adding $17$ to both sides of the inequality. $\newline$ s - 17 + 17 < -3 + 17 $\newline$ s < 14
Combine both parts: Now we combine both parts of the compound inequality using ＂or＂ as given in the original problem. $s \geq 17$ or s < 14