Solve for s. -2(s - 20) + 6 ≥ 10 ______

Distribute -2: Distribute -2 across the parentheses in the inequality -2(s - 20) + 6 ≥ 10. -2 * s + -2 * (-20) + 6 ≥ 10 -2s + 40 + 6 ≥ 10Combine like terms: Combine like terms on the left side of the inequality. -2s + 40 + 6 = -2s + 46 So, -2s + 46 ≥ 10Subtract 46: Subtract 46 from both sides of the inequality to isolate the term with the variable s. -2s + 46 - 46 ≥ 10 - 46 -2s ≥ -36Divide and reverse inequality: Divide both sides of the inequality by -2 to solve for s. Remember to reverse the inequality sign because we are dividing by a negative number. -2s / -2 ≤ -36 / -2 s ≤ 18

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Algebra 1

Solve advanced linear inequalities

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Q. Solve for

s

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-2(s - 20) + 6 \geq 10

Distribute $-2$ : Distribute $-2$ across the parentheses in the inequality $-2(s - 20) + 6 \geq 10$ .
$-2 \times s + -2 \times (-20) + 6 \geq 10$
$-2s + 40 + 6 \geq 10$
Combine like terms: Combine like terms on the left side of the inequality. $\newline$ $-2s + 40 + 6 = -2s + 46$ $\newline$ So, $-2s + 46 \geq 10$
Subtract $46$ : Subtract $46$ from both sides of the inequality to isolate the term with the variable $s$ . $\newline$ $-2s + 46 - 46 \geq 10 - 46$ $\newline$ $-2s \geq -36$
Divide and reverse inequality: Divide both sides of the inequality by $-2$ to solve for $s$ . Remember to reverse the inequality sign because we are dividing by a negative number. $\newline$ $-2s / -2 \leq -36 / -2$ $\newline$ $s \leq 18$