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Solve for pp.\newline1 \leq p + 16 < 2\newlineWrite your answer as a compound inequality with integers.\newlineChoices:\newline(A) 17 \leq p < 18\newline(B) -15 \leq p < -14\newline(C) -15 \leq p < 18\newline(D) 17 \leq p < -14

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Q. Solve for pp.\newline1p+16<21 \leq p + 16 < 2\newlineWrite your answer as a compound inequality with integers.\newlineChoices:\newline(A) 17p<1817 \leq p < 18\newline(B) 15p<14-15 \leq p < -14\newline(C) 15p<18-15 \leq p < 18\newline(D) 17p<1417 \leq p < -14
  1. Analyze Inequality: Analyze the compound inequality 1 \leq p + 16 < 2.\newlineTo isolate pp, we need to subtract 1616 from all parts of the inequality.
  2. Subtract 1616: Subtract 1616 from all parts of the inequality.\newline1 - 16 \leq p + 16 - 16 < 2 - 16\newline-15 \leq p < -14
  3. Check Solution: Check the solution to ensure it makes sense.\newlineIf we substitute pp with a number between 15-15 and 14-14, the original inequality 1 \leq p + 16 < 2 should hold true. Let's test p=14.5p = -14.5.\newline1 \leq -14.5 + 16 < 2\newline1 \leq 1.5 < 2 which is true.

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