Solve for k. {:[-2(k-5)=-6],[k=]:} Submit

Distribute -2: Distribute -2 in the first equation to solve for k. -2(k-5) = -6 -2k + 10 = -6Move constant term: Move the constant term to the right side of the equation. -2k + 10 - 10 = -6 - 10 -2k = -16Divide to isolate k: Divide both sides by -2 to isolate k. -2k / -2 = -16 / -2 k = 8Check solution: Check the solution with the second equation provided. k = 8 Since the second equation simply states k, and we have found k = 8, this confirms our solution.Problem completion: Since we have found a value for k and there is no contradiction with the second equation, we have completed the problem.

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Math Problems

Algebra 1

Solve advanced linear inequalities

Full solution

Q. Solve for

k

\newline

\begin{aligned} -2(k-5)&=-6 \ k&= \end{aligned}

Distribute $-2$ : Distribute $-2$ in the first equation to solve for $k$ . $-2(k-5) = -6$ $-2k + 10 = -6$
Move constant term: Move the constant term to the right side of the equation. $\newline$ $-2k + 10 - 10 = -6 - 10$ $\newline$ $-2k = -16$
Divide to isolate $k$ : Divide both sides by $-2$ to isolate $k$ . $\frac{-2k}{-2} = \frac{-16}{-2}$ $k = 8$
Check solution: Check the solution with the second equation provided. $\newline$ $k = 8$ $\newline$ Since the second equation simply states $k$ , and we have found $k = 8$ , this confirms our solution.
Problem completion: Since we have found a value for $k$ and there is no contradiction with the second equation, we have completed the problem.