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Solve for jj.\newlinej33\frac{j}{3} \leq 3

Full solution

Q. Solve for jj.\newlinej33\frac{j}{3} \leq 3
  1. Multiply by 33: To isolate jj, multiply both sides by 33.\newlineCalculation: j3×33×3\frac{j}{3} \times 3 \leq 3 \times 3\newlinej \leq 99

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