Solve for j. -2 < j + 13 ≤ 10 Write your answer as a compound inequality with integers. Choices: (A)-15 < j < -3 (B)-15 ≤ j ≤ -3 (C)-15 < j ≤ -3 (D)-15 ≤ j < -3

Simplify Inequality: Now, we simplify each part of the inequality. -15 < j ≤ -3Check Solution: We check our solution to make sure it makes sense. If we take a number between -15 and -3, say -10, and plug it back into the original inequality, we get: -2 < -10 + 13 ≤ 10 -2 < 3 ≤ 10 This is true, so our solution seems correct.

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Solve for $j$ . $\newline$ -2 < j + 13 \leq 10 $\newline$ Write your answer as a compound inequality with integers. $\newline$ Choices: $\newline$ (A) -15 < j < -3 $\newline$ (B) $-15 \leq j \leq -3$ $\newline$ (C) -15 < j \leq -3 $\newline$ (D) -15 \leq j < -3

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Math Problems

Algebra 1

Solve compound inequalities

Full solution

Q. Solve for

j

\newline

-2 < j + 13 \leq 10

\newline

Write your answer as a compound inequality with integers.

\newline

Choices:

\newline

(A)

-15 < j < -3

\newline

(B)

-15 \leq j \leq -3

\newline

(C)

-15 < j \leq -3

\newline

(D)

-15 \leq j < -3

Simplify Inequality: Now, we simplify each part of the inequality. $\newline$ -15 < j \leq -3
Check Solution: We check our solution to make sure it makes sense. $\newline$ If we take a number between $-15$ and $-3$ , say $-10$ , and plug it back into the original inequality, we get: $\newline$ -2 < -10 + 13 \leq 10 $\newline$ -2 < 3 \leq 10 $\newline$ This is true, so our solution seems correct.