Solve for j. -1 < j + 4 ≤ 3 Write your answer as a compound inequality with integers. Choices: (A)-5 < j < -1 (B)-5 ≤ j ≤ -1 (C)-5 < j ≤ -1 (D)-5 ≤ j < -1

Undo addition of 4: To isolate j, we need to undo the addition of 4 to j. We will subtract 4 from all parts of the inequality. -1 < j + 4 ≤ 3 -1 - 4 < j + 4 - 4 ≤ 3 - 4 -5 < j ≤ -1

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Solve for $j$ . $\newline$ -1 < j + 4 \leq 3 $\newline$ Write your answer as a compound inequality with integers. $\newline$ Choices: $\newline$ (A) -5 < j < -1 $\newline$ (B) $-5 \leq j \leq -1$ $\newline$ (C) -5 < j \leq -1 $\newline$ (D) -5 \leq j < -1

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Math Problems

Algebra 1

Solve compound inequalities

Full solution

Q. Solve for

j

\newline

-1 < j + 4 \leq 3

\newline

Write your answer as a compound inequality with integers.

\newline

Choices:

\newline

(A)

-5 < j < -1

\newline

(B)

-5 \leq j \leq -1

\newline

(C)

-5 < j \leq -1

\newline

(D)

-5 \leq j < -1

Undo addition of $4$ : To isolate $j$ , we need to undo the addition of $4$ to $j$ . We will subtract $4$ from all parts of the inequality.-1 < j + 4 \leq 3-1 - 4 < j + 4 - 4 \leq 3 - 4-5 < j \leq -1